#103348: "Better algorithm in order to get less repeats"
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# | Status | Votes | Game | Type | Title | Last update |
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وصف مفصل
• يرجى نسخ / لصق رسالة الخطأ التي تراها على الشاشة ، إن وجدت.
As discussed here: boardgamearena.com/forum/viewtopic.php?t=27740&start=30
Possible solutions:
a) Algorithm 1 (13 distinct cards out of 110 are chosen randomly and for each chosen card 1 word out of 5 is chosen randomly)
or
b) Algorithm 2 (13 distinct words out of 550 are chosen randomly)
or
c) Give players the opportunity to choose 1 out of 5 words (as in the physical game)• يرجى توضيح ما تريد القيام به ، ماذا فعلت وما حدث
• ما هو متصفحك؟
Mozilla v5
• يرجى نسخ / لصق النص المعروض باللغة الإنجليزية بدلاً من لغتك. إذا كان لديك لقطة شاشة لهذا الخطأ (ممارسة جيدة) ، يمكنك استخدام Imgur.com لتحميله ونسخ / لصق الرابط هنا.
As discussed here: boardgamearena.com/forum/viewtopic.php?t=27740&start=30
Possible solutions:
a) Algorithm 1 (13 distinct cards out of 110 are chosen randomly and for each chosen card 1 word out of 5 is chosen randomly)
or
b) Algorithm 2 (13 distinct words out of 550 are chosen randomly)
or
c) Give players the opportunity to choose 1 out of 5 words (as in the physical game)• هل هذا النص متاح في translation system ؟ إذا كانت الإجابة بنعم ، فهل تمت ترجمتها لأكثر من 24 ساعة؟
• ما هو متصفحك؟
Mozilla v5
• يرجى توضيح اقتراحك بدقة وإيجاز بحيث يكون من السهل قدر الإمكان فهم ما تعنيه.
As discussed here: boardgamearena.com/forum/viewtopic.php?t=27740&start=30
Possible solutions:
a) Algorithm 1 (13 distinct cards out of 110 are chosen randomly and for each chosen card 1 word out of 5 is chosen randomly)
or
b) Algorithm 2 (13 distinct words out of 550 are chosen randomly)
or
c) Give players the opportunity to choose 1 out of 5 words (as in the physical game)• ما هو متصفحك؟
Mozilla v5
• ما الذي تم عرضه على الشاشة عندما تم حظرك (شاشة فارغة؟ جزء من واجهة اللعبة؟ رسالة خطأ؟)
As discussed here: boardgamearena.com/forum/viewtopic.php?t=27740&start=30
Possible solutions:
a) Algorithm 1 (13 distinct cards out of 110 are chosen randomly and for each chosen card 1 word out of 5 is chosen randomly)
or
b) Algorithm 2 (13 distinct words out of 550 are chosen randomly)
or
c) Give players the opportunity to choose 1 out of 5 words (as in the physical game)• ما هو متصفحك؟
Mozilla v5
• أي جزء من القواعد تم مخالفته في تصميم التبني لدى BGA
As discussed here: boardgamearena.com/forum/viewtopic.php?t=27740&start=30
Possible solutions:
a) Algorithm 1 (13 distinct cards out of 110 are chosen randomly and for each chosen card 1 word out of 5 is chosen randomly)
or
b) Algorithm 2 (13 distinct words out of 550 are chosen randomly)
or
c) Give players the opportunity to choose 1 out of 5 words (as in the physical game)• هل انتهاك القواعد مرئي عند إعادة اللعب؟ إذا كانت الإجابة بنعم ، فبأي رقم؟
• ما هو متصفحك؟
Mozilla v5
• ما هو نشاط اللعبة الذي أردت القيام به؟
As discussed here: boardgamearena.com/forum/viewtopic.php?t=27740&start=30
Possible solutions:
a) Algorithm 1 (13 distinct cards out of 110 are chosen randomly and for each chosen card 1 word out of 5 is chosen randomly)
or
b) Algorithm 2 (13 distinct words out of 550 are chosen randomly)
or
c) Give players the opportunity to choose 1 out of 5 words (as in the physical game)• ماذا تحاول أن تفعل لتحريك هذا العمل اللعبة؟
• ماذا حدث عند محاولة القيام بهذا (رسالة خطأ ، رسالة شريط حالة اللعبة ، ...)؟
• ما هو متصفحك؟
Mozilla v5
• في أي خطوة من اللعبة حدثت المشكلة (ما هو تعليمة اللعبة الحالية)؟
As discussed here: boardgamearena.com/forum/viewtopic.php?t=27740&start=30
Possible solutions:
a) Algorithm 1 (13 distinct cards out of 110 are chosen randomly and for each chosen card 1 word out of 5 is chosen randomly)
or
b) Algorithm 2 (13 distinct words out of 550 are chosen randomly)
or
c) Give players the opportunity to choose 1 out of 5 words (as in the physical game)• ماذا حدث عند محاولة إجراء هذه الحركة داخل اللعبة (رسالة خطأ ، رسالة شريط حالة اللعبة ، ...)؟
• ما هو متصفحك؟
Mozilla v5
• يرجى وصف مشكلة العرض. إذا كان لديك لقطة شاشة لهذا الخطأ (ممارسة جيدة) ، يمكنك استخدام Imgur.com لتحميله ونسخ / لصق الرابط هنا.
As discussed here: boardgamearena.com/forum/viewtopic.php?t=27740&start=30
Possible solutions:
a) Algorithm 1 (13 distinct cards out of 110 are chosen randomly and for each chosen card 1 word out of 5 is chosen randomly)
or
b) Algorithm 2 (13 distinct words out of 550 are chosen randomly)
or
c) Give players the opportunity to choose 1 out of 5 words (as in the physical game)• ما هو متصفحك؟
Mozilla v5
• يرجى نسخ / لصق النص المعروض باللغة الإنجليزية بدلاً من لغتك. إذا كان لديك لقطة شاشة لهذا الخطأ (ممارسة جيدة) ، يمكنك استخدام Imgur.com لتحميله ونسخ / لصق الرابط هنا.
As discussed here: boardgamearena.com/forum/viewtopic.php?t=27740&start=30
Possible solutions:
a) Algorithm 1 (13 distinct cards out of 110 are chosen randomly and for each chosen card 1 word out of 5 is chosen randomly)
or
b) Algorithm 2 (13 distinct words out of 550 are chosen randomly)
or
c) Give players the opportunity to choose 1 out of 5 words (as in the physical game)• هل هذا النص متاح في translation system ؟ إذا كانت الإجابة بنعم ، فهل تمت ترجمتها لأكثر من 24 ساعة؟
• ما هو متصفحك؟
Mozilla v5
• يرجى توضيح اقتراحك بدقة وإيجاز بحيث يكون من السهل قدر الإمكان فهم ما تعنيه.
As discussed here: boardgamearena.com/forum/viewtopic.php?t=27740&start=30
Possible solutions:
a) Algorithm 1 (13 distinct cards out of 110 are chosen randomly and for each chosen card 1 word out of 5 is chosen randomly)
or
b) Algorithm 2 (13 distinct words out of 550 are chosen randomly)
or
c) Give players the opportunity to choose 1 out of 5 words (as in the physical game)• ما هو متصفحك؟
Mozilla v5
سجل التاريخ
Sorry for that but I'm not ready to invest my time in Just One anymore
So for example, if $wordID is 1, it would take the first word for every 13 card?
That would be like 5 options for the card index combinations.
I guess the fix would be to use a different word index for every of the 13 cards. that would be like 5^13 = 1.220.703.125 options.
So, you would have to recalculate the wordID for each card, instead of computing it once on game start. Seems to be a pretty trivial change, isn't it?
If you would share code I could take a look at that.
I don't have an idea why this algo would be biased towards specific words. I guess that either your card shuffling or the index selection is flawed. Are you using random_int(4) for that wordID? And how do you shuffle cards?
We are forced to use bga_rand() and I'm using it.
However for cardIds I create an array from 0 to 549, use PHP shuffle() method and take first 13 or first 550 depending on a game option.
Consider two different games.
Assume you drew [b]two[/b] equal [b]cards[/b] in both games.
The propability that [b]both[/b] cards have the same word (two repetitions) is:
- 20 % in your variant (you have to select the same index in the second game as in the first, and both words will repeat)
- 4 % in the variant with indices per card (as you select a different index for each card).
If you have 3 same cards, it's always 20% in your variant, and 0.8% in the index-per-card-variant.
I guess that would just feel more random to players. If you have one repetition, you don't notice it. If you have [b]two[/b] repetitions, you might notice it.
So, could you pretty please change it? :)
اضف لهذا البلاغ
- تعريف طاولة/تعريف حركة
- هل حلَت F5 المشكلة؟
- هل ظهرت المشكلة عدة مرات؟ كل مرة؟ بطريقة عشوائية؟
- إذا كان لديك لقطة شاشة لهذا الخطأ (ممارسة جيدة) ، يمكنك استخدام Imgur.com لتحميله ونسخ / لصق الرابط هنا.