#108703: "Tiebreak when the instant win card is activated"
ما هو هذا التقرير؟
ماذا حدث؟ يرجى اختيار من أدناه
ماذا حدث؟ يرجى اختيار من أدناه
يرجى التحقق مما إذا كان هناك بالفعل تقرير عن نفس الموضوع
إذا كانت الإجابة بنعم ، يرجى التصويت لهذا التقرير. يتم إعطاء التقارير ذات أكبر عدد من الأصوات الأولوية!
| # | Status | Votes | Game | Type | Title | Last update |
|---|
وصف مفصل
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• يرجى نسخ / لصق رسالة الخطأ التي تراها على الشاشة ، إن وجدت.
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. -
• يرجى توضيح ما تريد القيام به ، ماذا فعلت وما حدث
End of game standings
• ما هو متصفحك؟
Google Chrome v120
-
• يرجى نسخ / لصق النص المعروض باللغة الإنجليزية بدلاً من لغتك. إذا لديك لقطة شاشة عن هذا الخطأ (من المفضل)، يمكنك استخدام خدمة إستضافة للصور من اختيارك (snipboard.io مثلاً) لتحميلها و نسخ/لصق الرابط هنا. هل هذا النص متاح في translation system ؟ إذا كانت الإجابة بنعم ، فهل تمت ترجمتها لأكثر من 24 ساعة؟
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. • ما هو متصفحك؟
Google Chrome v120
-
• يرجى توضيح اقتراحك بدقة وإيجاز بحيث يكون من السهل قدر الإمكان فهم ما تعنيه.
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. • ما هو متصفحك؟
Google Chrome v120
-
• ما الذي تم عرضه على الشاشة عندما تم حظرك (شاشة فارغة؟ جزء من واجهة اللعبة؟ رسالة خطأ؟)
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. • ما هو متصفحك؟
Google Chrome v120
-
• أي جزء من القواعد تم مخالفته في تصميم التبني لدى BGA
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. -
• هل انتهاك القواعد مرئي عند إعادة اللعب؟ إذا كانت الإجابة بنعم ، فبأي رقم؟
End of game standings
• ما هو متصفحك؟
Google Chrome v120
-
• ما هو نشاط اللعبة الذي أردت القيام به؟
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. -
• ماذا تحاول أن تفعل لتحريك هذا العمل اللعبة؟
End of game standings
-
• ماذا حدث عند محاولة القيام بهذا (رسالة خطأ ، رسالة شريط حالة اللعبة ، ...)؟
• ما هو متصفحك؟
Google Chrome v120
-
• في أي خطوة من اللعبة حدثت المشكلة (ما هو تعليمة اللعبة الحالية)؟
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. -
• ماذا حدث عند محاولة إجراء هذه الحركة داخل اللعبة (رسالة خطأ ، رسالة شريط حالة اللعبة ، ...)؟
End of game standings
• ما هو متصفحك؟
Google Chrome v120
-
• يرجى وصف مشكلة العرض. إذا لديك لقطة شاشة عن هذا الخطأ (من المفضل)، يمكنك استخدام خدمة إستضافة للصور من اختيارك (snipboard.io مثلاً) لتحميلها و نسخ/لصق الرابط هنا.
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. • ما هو متصفحك؟
Google Chrome v120
-
• يرجى نسخ / لصق النص المعروض باللغة الإنجليزية بدلاً من لغتك. إذا لديك لقطة شاشة عن هذا الخطأ (من المفضل)، يمكنك استخدام خدمة إستضافة للصور من اختيارك (snipboard.io مثلاً) لتحميلها و نسخ/لصق الرابط هنا. هل هذا النص متاح في translation system ؟ إذا كانت الإجابة بنعم ، فهل تمت ترجمتها لأكثر من 24 ساعة؟
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. • ما هو متصفحك؟
Google Chrome v120
-
• يرجى توضيح اقتراحك بدقة وإيجاز بحيث يكون من السهل قدر الإمكان فهم ما تعنيه.
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. • ما هو متصفحك؟
Google Chrome v120
سجل التاريخ
For me, when someone instant win, then all others having 0 will tie them second (that's what happened to you, this is not random placement).
اضف لهذا البلاغ
- تعريف طاولة/تعريف حركة
- هل حلَت F5 المشكلة؟
- هل ظهرت المشكلة عدة مرات؟ كل مرة؟ بطريقة عشوائية؟
- إذا لديك لقطة شاشة عن هذا الخطأ (من المفضل)، يمكنك استخدام خدمة إستضافة للصور من اختيارك (snipboard.io مثلاً) لتحميلها و نسخ/لصق الرابط هنا.
